(2)/(3)z+6=12

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Solution for (2)/(3)z+6=12 equation: 



(2)/(3)z+6=12

We move all terms to the left:

(2)/(3)z+6-(12)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

2/3z-6=0

We multiply all the terms by the denominator


-6*3z+2=0

Wy multiply elements

-18z+2=0

We move all terms containing z to the left, all other terms to the right

-18z=-2

z=-2/-18

z=1/9

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