(2)/(4n-7)=(2)/(2n-5)

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Solution for (2)/(4n-7)=(2)/(2n-5) equation: 


D( n )

4*n-7 = 0

2*n-5 = 0

4*n-7 = 0

4*n-7 = 0

4*n-7 = 0 // + 7

4*n = 7 // : 4

n = 7/4

2*n-5 = 0

2*n-5 = 0

2*n-5 = 0 // + 5

2*n = 5 // : 2

n = 5/2

n in (-oo:7/4) U (7/4:5/2) U (5/2:+oo)

2/(4*n-7) = 2/(2*n-5) // - 2/(2*n-5)

2/(4*n-7)-(2/(2*n-5)) = 0

2/(4*n-7)-2*(2*n-5)^-1 = 0

2/(4*n-7)-2/(2*n-5) = 0

(2*(2*n-5))/((4*n-7)*(2*n-5))+(-2*(4*n-7))/((4*n-7)*(2*n-5)) = 0

2*(2*n-5)-2*(4*n-7) = 0

4-4*n = 0

(4-4*n)/((4*n-7)*(2*n-5)) = 0

(4-4*n)/((4*n-7)*(2*n-5)) = 0 // * (4*n-7)*(2*n-5)

4-4*n = 0

4-4*n = 0 // - 4

-4*n = -4 // : -4

n = -4/(-4)

n = 1

n = 1

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