(2)/(5)-7=(12)/(5)h-2h+3

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Solution for (2)/(5)-7=(12)/(5)h-2h+3 equation: 



(2)/(5)-7=(12)/(5)h-2h+3

We move all terms to the left:

(2)/(5)-7-((12)/(5)h-2h+3)=0



Domain of the equation: 5h-2h+3)!=0

h∈R



We add all the numbers together, and all the variables

-(-2h+12/5h+3)-7+2/5=0

We get rid of parentheses

2h-12/5h-3-7+2/5=0

We calculate fractions


2h-3-7=0

We add all the numbers together, and all the variables

2h-10=0

We move all terms containing h to the left, all other terms to the right

2h=10

h=10/2

h=5

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