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(2)/(5)h+6=8
We move all terms to the left:
(2)/(5)h+6-(8)=0
Domain of the equation: 5h!=0We add all the numbers together, and all the variables
h!=0/5
h!=0
h∈R
2/5h-2=0
We multiply all the terms by the denominator
-2*5h+2=0
Wy multiply elements
-10h+2=0
We move all terms containing h to the left, all other terms to the right
-10h=-2
h=-2/-10
h=1/5
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