(2)/(5)s-2+3(s-11)=50

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Solution for (2)/(5)s-2+3(s-11)=50 equation:



(2)/(5)s-2+3(s-11)=50
We move all terms to the left:
(2)/(5)s-2+3(s-11)-(50)=0
Domain of the equation: 5s!=0
s!=0/5
s!=0
s∈R
We add all the numbers together, and all the variables
2/5s+3(s-11)-52=0
We multiply parentheses
2/5s+3s-33-52=0
We multiply all the terms by the denominator
3s*5s-33*5s-52*5s+2=0
Wy multiply elements
15s^2-165s-260s+2=0
We add all the numbers together, and all the variables
15s^2-425s+2=0
a = 15; b = -425; c = +2;
Δ = b2-4ac
Δ = -4252-4·15·2
Δ = 180505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-\sqrt{180505}}{2*15}=\frac{425-\sqrt{180505}}{30} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+\sqrt{180505}}{2*15}=\frac{425+\sqrt{180505}}{30} $

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