(2)/(t)=(t)/(-5t-12)

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Solution for (2)/(t)=(t)/(-5t-12) equation:


D( t )

t = 0

-5*t-12 = 0

t = 0

t = 0

-5*t-12 = 0

-5*t-12 = 0

-5*t-12 = 0 // + 12

-5*t = 12 // : -5

t = 12/(-5)

t = -12/5

t in (-oo:-12/5) U (-12/5:0) U (0:+oo)

2/t = t/(-5*t-12) // - t/(-5*t-12)

2/t-(t/(-5*t-12)) = 0

(-1*t)/(-5*t-12)+2/t = 0

(-1*t^2)/(t*(-5*t-12))+(2*(-5*t-12))/(t*(-5*t-12)) = 0

2*(-5*t-12)-1*t^2 = 0

-t^2-10*t-24 = 0

-t^2-10*t-24 = 0

-1*(t^2+10*t+24) = 0

t^2+10*t+24 = 0

DELTA = 10^2-(1*4*24)

DELTA = 4

DELTA > 0

t = (4^(1/2)-10)/(1*2) or t = (-4^(1/2)-10)/(1*2)

t = -4 or t = -6

-1*(t+6)*(t+4) = 0

(-1*(t+6)*(t+4))/(t*(-5*t-12)) = 0

(-1*(t+6)*(t+4))/(t*(-5*t-12)) = 0 // * t*(-5*t-12)

-1*(t+6)*(t+4) = 0

( -1 )

-1 = 0

t belongs to the empty set

( t+4 )

t+4 = 0 // - 4

t = -4

( t+6 )

t+6 = 0 // - 6

t = -6

t in { -4, -6 }

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