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(2)1/2(x+2)=(8)1/2(3-x)
We move all terms to the left:
(2)1/2(x+2)-((8)1/2(3-x))=0
Domain of the equation: 2(x+2)!=0
x∈R
Domain of the equation: 2(3-x))!=0We add all the numbers together, and all the variables
x∈R
21/2(x+2)-(81/2(-1x+3))=0
We calculate fractions
(42x(-)/(2(x+2)*2(-1x+3)))+(-162xx/(2(x+2)*2(-1x+3)))=0
We calculate terms in parentheses: +(42x(-)/(2(x+2)*2(-1x+3))), so:
42x(-)/(2(x+2)*2(-1x+3))
We add all the numbers together, and all the variables
42x0/(2(x+2)*2(-1x+3))
We multiply all the terms by the denominator
42x0
We add all the numbers together, and all the variables
42x
Back to the equation:
+(42x)
We calculate terms in parentheses: +(-162xx/(2(x+2)*2(-1x+3))), so:We get rid of parentheses
-162xx/(2(x+2)*2(-1x+3))
We multiply all the terms by the denominator
-162xx
Back to the equation:
+(-162xx)
42x-162xx=0
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