(2)=8+40.8t-16t2

Solution for (2)=8+40.8t-16t2 equation:

(2)=8+40.8t-16t^2

We move all terms to the left:

(2)-(8+40.8t-16t^2)=0

We get rid of parentheses

16t^2-40.8t-8+2=0

We add all the numbers together, and all the variables

16t^2-40.8t-6=0

a = 16; b = -40.8; c = -6;
Δ = b2-4ac
Δ = -40.82-4·16·(-6)
Δ = 2048.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40.8)-\sqrt{2048.64}}{2*16}=\frac{40.8-\sqrt{2048.64}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40.8)+\sqrt{2048.64}}{2*16}=\frac{40.8+\sqrt{2048.64}}{32}
$