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(2(11/8y))+2y=190
We move all terms to the left:
(2(11/8y))+2y-(190)=0
Domain of the equation: 8y))!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(2(+11/8y))+2y-190=0
We add all the numbers together, and all the variables
2y+(2(+11/8y))-190=0
We multiply all the terms by the denominator
2y*8y))+(2(-190*8y))+11=0
Wy multiply elements
16y^2-1520y=0
a = 16; b = -1520; c = 0;
Δ = b2-4ac
Δ = -15202-4·16·0
Δ = 2310400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2310400}=1520$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1520)-1520}{2*16}=\frac{0}{32} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1520)+1520}{2*16}=\frac{3040}{32} =95 $
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