(2*2*2*2-3*5)q+13=(2*9-4*4)q+0

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Solution for (2*2*2*2-3*5)q+13=(2*9-4*4)q+0 equation:


(2*2*2*2-3*5)q+13=(2*9-4*4)q

We simplify the equation to the form, which is simple to understand 
(2*2*2*2-3*5)q+13=(2*9-4*4)q

Simplifying:
(+4*2*2-3*5)*q+13=(2*9-4*4)*q

Simplifying:
(+8*2-3*5)*q+13=(2*9-4*4)*q

Simplifying:
(+16-3*5)*q+13=(2*9-4*4)*q

Simplifying:
(+16-15)*q+13=(2*9-4*4)*q

Simplifying:
(+16-15)*q+13=(+18-4*4)*q

Simplifying:
(+16-15)*q+13=(+18-16)*q

Simplifying terms in parentheses
(+1)*q+13=(+18-16)*q

Simplifying terms in parentheses
(+1)*q+13=(+2)*q

Reorder the terms in parentheses
(+1q)+13=(+2)*q

Remove unnecessary parentheses
+1q+13=(+2)*q

Reorder the terms in parentheses
+1q+13=(+2q)

Remove unnecessary parentheses
+1q+13=+2q

We move all terms containing q to the left and all other terms to the right. 
+1q-2q=0-13

We simplify left and right side of the equation. 
-1q=-13

We divide both sides of the equation by -1 to get q. 
q=13

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