(2+12)+r=2+(12+r)

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Solution for (2+12)+r=2+(12+r) equation: 



(2+12)+r=2+(12+r)

We move all terms to the left:

(2+12)+r-(2+(12+r))=0

We add all the numbers together, and all the variables

r-(2+(r+12))+14=0



We calculate terms in parentheses: -(2+(r+12)), so:

2+(r+12)

determiningTheFunctionDomain
(r+12)+2

We get rid of parentheses

r+12+2

We add all the numbers together, and all the variables

r+14

Back to the equation:

-(r+14)



We get rid of parentheses

r-r-14+14=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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