(2+2(a-3)+5)/(3a)=3

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Solution for (2+2(a-3)+5)/(3a)=3 equation: 



(2+2(a-3)+5)/(3a)=3

We move all terms to the left:

(2+2(a-3)+5)/(3a)-(3)=0



Domain of the equation: 3a!=0

a!=0/3

a!=0

a∈R



We multiply all the terms by the denominator


(2+2(a-3)+5)-3*3a=0



We calculate terms in parentheses: +(2+2(a-3)+5), so:

2+2(a-3)+5

determiningTheFunctionDomain
2(a-3)+2+5

We add all the numbers together, and all the variables

2(a-3)+7

We multiply parentheses

2a-6+7

We add all the numbers together, and all the variables

2a+1

Back to the equation:

+(2a+1)



Wy multiply elements

(2a+1)-9a=0

We get rid of parentheses

2a-9a+1=0

We add all the numbers together, and all the variables

-7a+1=0

We move all terms containing a to the left, all other terms to the right

-7a=-1

a=-1/-7

a=1/7

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