(2+2i)-(5+I)=

Solution for (2+2i)-(5+I)= equation:

Simplifying
(2 + 2i) + -1(5 + I) = 0

Remove parenthesis around (2 + 2i)
2 + 2i + -1(5 + I) = 0
2 + 2i + (5 * -1 + I * -1) = 0
2 + 2i + (-5 + -1I) = 0

Reorder the terms:
2 + -5 + -1I + 2i = 0

Combine like terms: 2 + -5 = -3
-3 + -1I + 2i = 0

Solving
-3 + -1I + 2i = 0

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -1I + 3 + 2i = 0 + 3

Reorder the terms:
-3 + 3 + -1I + 2i = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1I + 2i = 0 + 3
-1I + 2i = 0 + 3

Combine like terms: 0 + 3 = 3
-1I + 2i = 3

Add '-2i' to each side of the equation.
-1I + 2i + -2i = 3 + -2i

Combine like terms: 2i + -2i = 0
-1I + 0 = 3 + -2i
-1I = 3 + -2i

Divide each side by '-1'.
I = -3 + 2i

Simplifying
I = -3 + 2i