(2+2j)(3-2j)=

Solution for (2+2j)(3-2j)= equation:

Simplifying
(2 + 2j)(3 + -2j) = 0

Multiply (2 + 2j) * (3 + -2j)
(2(3 + -2j) + 2j * (3 + -2j)) = 0
((3 * 2 + -2j * 2) + 2j * (3 + -2j)) = 0
((6 + -4j) + 2j * (3 + -2j)) = 0
(6 + -4j + (3 * 2j + -2j * 2j)) = 0
(6 + -4j + (6j + -4j2)) = 0

Combine like terms: -4j + 6j = 2j
(6 + 2j + -4j2) = 0

Solving
6 + 2j + -4j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2'.
2(3 + j + -2j2) = 0

Factor a trinomial.
2((3 + -2j)(1 + j)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(3 + -2j)' equal to zero and attempt to solve:

Simplifying
3 + -2j = 0

Solving
3 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2j = 0 + -3
-2j = 0 + -3

Combine like terms: 0 + -3 = -3
-2j = -3

Divide each side by '-2'.
j = 1.5

Simplifying
j = 1.5
Subproblem 2
Set the factor '(1 + j)' equal to zero and attempt to solve:

Simplifying
1 + j = 0

Solving
1 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + j = 0 + -1
j = 0 + -1

Combine like terms: 0 + -1 = -1
j = -1

Simplifying
j = -1
Solution
j = {1.5, -1}