(2+3i)(2-3i)=

Solution for (2+3i)(2-3i)= equation:

Simplifying
(2 + 3i)(2 + -3i) = 0

Multiply (2 + 3i) * (2 + -3i)
(2(2 + -3i) + 3i * (2 + -3i)) = 0
((2 * 2 + -3i * 2) + 3i * (2 + -3i)) = 0
((4 + -6i) + 3i * (2 + -3i)) = 0
(4 + -6i + (2 * 3i + -3i * 3i)) = 0
(4 + -6i + (6i + -9i2)) = 0

Combine like terms: -6i + 6i = 0
(4 + 0 + -9i2) = 0
(4 + -9i2) = 0

Solving
4 + -9i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -9i2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -9i2 = 0 + -4
-9i2 = 0 + -4

Combine like terms: 0 + -4 = -4
-9i2 = -4

Divide each side by '-9'.
i2 = 0.4444444444

Simplifying
i2 = 0.4444444444

Take the square root of each side:
i = {-0.666666667, 0.666666667}