(2+3i)(2-i)=9

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Solution for (2+3i)(2-i)=9 equation: 



(2+3i)(2-i)=9

We move all terms to the left:

(2+3i)(2-i)-(9)=0

We add all the numbers together, and all the variables

(3i+2)(-1i+2)-9=0

We multiply parentheses ..

(-3i^2+6i-2i+4)-9=0

We get rid of parentheses

-3i^2+6i-2i+4-9=0

We add all the numbers together, and all the variables

-3i^2+4i-5=0

a = -3; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-3)·(-5)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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