(2+3i)(x+yi)=16+11i

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Solution for (2+3i)(x+yi)=16+11i equation: 


Simplifying
(2 + 3i)(x + yi) = 16 + 11i

Reorder the terms:
(2 + 3i)(iy + x) = 16 + 11i

Multiply (2 + 3i) * (iy + x)
(2(iy + x) + 3i * (iy + x)) = 16 + 11i
((iy * 2 + x * 2) + 3i * (iy + x)) = 16 + 11i
((2iy + 2x) + 3i * (iy + x)) = 16 + 11i
(2iy + 2x + (iy * 3i + x * 3i)) = 16 + 11i

Reorder the terms:
(2iy + 2x + (3ix + 3i2y)) = 16 + 11i
(2iy + 2x + (3ix + 3i2y)) = 16 + 11i

Reorder the terms:
(3ix + 2iy + 3i2y + 2x) = 16 + 11i
(3ix + 2iy + 3i2y + 2x) = 16 + 11i

Solving
3ix + 2iy + 3i2y + 2x = 16 + 11i

Solving for variable 'i'.

Reorder the terms:
-16 + -11i + 3ix + 2iy + 3i2y + 2x = 16 + 11i + -16 + -11i

Reorder the terms:
-16 + -11i + 3ix + 2iy + 3i2y + 2x = 16 + -16 + 11i + -11i

Combine like terms: 16 + -16 = 0
-16 + -11i + 3ix + 2iy + 3i2y + 2x = 0 + 11i + -11i
-16 + -11i + 3ix + 2iy + 3i2y + 2x = 11i + -11i

Combine like terms: 11i + -11i = 0
-16 + -11i + 3ix + 2iy + 3i2y + 2x = 0

The solution to this equation could not be determined.

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