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(2+3x)*3-128-12x=x+6(2x+1)
We move all terms to the left:
(2+3x)*3-128-12x-(x+6(2x+1))=0
We add all the numbers together, and all the variables
(3x+2)*3-12x-(x+6(2x+1))-128=0
We add all the numbers together, and all the variables
-12x+(3x+2)*3-(x+6(2x+1))-128=0
We multiply parentheses
-12x+9x-(x+6(2x+1))+6-128=0
We calculate terms in parentheses: -(x+6(2x+1)), so:We add all the numbers together, and all the variables
x+6(2x+1)
We multiply parentheses
x+12x+6
We add all the numbers together, and all the variables
13x+6
Back to the equation:
-(13x+6)
-3x-(13x+6)-122=0
We get rid of parentheses
-3x-13x-6-122=0
We add all the numbers together, and all the variables
-16x-128=0
We move all terms containing x to the left, all other terms to the right
-16x=128
x=128/-16
x=-8
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