(2+3x)+(x-22)=180

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Solution for (2+3x)+(x-22)=180 equation: 



(2+3x)+(x-22)=180

We move all terms to the left:

(2+3x)+(x-22)-(180)=0

We add all the numbers together, and all the variables

(3x+2)+(x-22)-180=0

We get rid of parentheses

3x+x+2-22-180=0

We add all the numbers together, and all the variables

4x-200=0

We move all terms containing x to the left, all other terms to the right

4x=200

x=200/4

x=50

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