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(2+4i)(-3-5i)=14-22i
We move all terms to the left:
(2+4i)(-3-5i)-(14-22i)=0
We add all the numbers together, and all the variables
(4i+2)(-5i-3)-(-22i+14)=0
We get rid of parentheses
(4i+2)(-5i-3)+22i-14=0
We multiply parentheses ..
(-20i^2-12i-10i-6)+22i-14=0
We get rid of parentheses
-20i^2-12i-10i+22i-6-14=0
We add all the numbers together, and all the variables
-20i^2-20=0
a = -20; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·(-20)·(-20)
Δ = -1600
Delta is less than zero, so there is no solution for the equation
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