(2+4i)(2-4i)=0

Solution for (2+4i)(2-4i)=0 equation:

Simplifying
(2 + 4i)(2 + -4i) = 0

Multiply (2 + 4i) * (2 + -4i)
(2(2 + -4i) + 4i * (2 + -4i)) = 0
((2 * 2 + -4i * 2) + 4i * (2 + -4i)) = 0
((4 + -8i) + 4i * (2 + -4i)) = 0
(4 + -8i + (2 * 4i + -4i * 4i)) = 0
(4 + -8i + (8i + -16i2)) = 0

Combine like terms: -8i + 8i = 0
(4 + 0 + -16i2) = 0
(4 + -16i2) = 0

Solving
4 + -16i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -16i2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -16i2 = 0 + -4
-16i2 = 0 + -4

Combine like terms: 0 + -4 = -4
-16i2 = -4

Divide each side by '-16'.
i2 = 0.25

Simplifying
i2 = 0.25

Take the square root of each side:
i = {-0.5, 0.5}