(2+4i)(7-2i)-(6+i)=16+23i

Solution for (2+4i)(7-2i)-(6+i)=16+23i equation:

(2+4i)(7-2i)-(6+i)=16+23i

We move all terms to the left:

(2+4i)(7-2i)-(6+i)-(16+23i)=0

We add all the numbers together, and all the variables

(4i+2)(-2i+7)-(i+6)-(23i+16)=0

We get rid of parentheses

(4i+2)(-2i+7)-i-23i-6-16=0

We multiply parentheses ..

(-8i^2+28i-4i+14)-i-23i-6-16=0

We add all the numbers together, and all the variables

(-8i^2+28i-4i+14)-24i-22=0

We get rid of parentheses

-8i^2+28i-4i-24i+14-22=0

We add all the numbers together, and all the variables

-8i^2-8=0

a = -8; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-8)·(-8)
Δ = -256
Delta is less than zero, so there is no solution for the equation