(2+4j)x(2-4j)=

Solution for (2+4j)x(2-4j)= equation:

Simplifying
(2 + 4j) * x(2 + -4j) = 0

Reorder the terms for easier multiplication:
x(2 + 4j)(2 + -4j) = 0

Multiply (2 + 4j) * (2 + -4j)
x(2(2 + -4j) + 4j * (2 + -4j)) = 0
x((2 * 2 + -4j * 2) + 4j * (2 + -4j)) = 0
x((4 + -8j) + 4j * (2 + -4j)) = 0
x(4 + -8j + (2 * 4j + -4j * 4j)) = 0
x(4 + -8j + (8j + -16j2)) = 0

Combine like terms: -8j + 8j = 0
x(4 + 0 + -16j2) = 0
x(4 + -16j2) = 0
(4 * x + -16j2 * x) = 0

Reorder the terms:
(-16j2x + 4x) = 0
(-16j2x + 4x) = 0

Solving
-16j2x + 4x = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-16j2x + 4x + -4x = 0 + -4x

Combine like terms: 4x + -4x = 0
-16j2x + 0 = 0 + -4x
-16j2x = 0 + -4x
Remove the zero:
-16j2x = -4x

Divide each side by '-16x'.
j2 = 0.25

Simplifying
j2 = 0.25

Take the square root of each side:
j = {-0.5, 0.5}