(2+5i)+(6-I)=

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Solution for (2+5i)+(6-I)= equation:


Simplifying
(2 + 5i) + (6 + -1I) = 0

Remove parenthesis around (2 + 5i)
2 + 5i + (6 + -1I) = 0

Remove parenthesis around (6 + -1I)
2 + 5i + 6 + -1I = 0

Reorder the terms:
2 + 6 + -1I + 5i = 0

Combine like terms: 2 + 6 = 8
8 + -1I + 5i = 0

Solving
8 + -1I + 5i = 0

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -1I + -8 + 5i = 0 + -8

Reorder the terms:
8 + -8 + -1I + 5i = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1I + 5i = 0 + -8
-1I + 5i = 0 + -8

Combine like terms: 0 + -8 = -8
-1I + 5i = -8

Add '-5i' to each side of the equation.
-1I + 5i + -5i = -8 + -5i

Combine like terms: 5i + -5i = 0
-1I + 0 = -8 + -5i
-1I = -8 + -5i

Divide each side by '-1'.
I = 8 + 5i

Simplifying
I = 8 + 5i

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