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(2+5i)-(-6+3i)=8+2i
We move all terms to the left:
(2+5i)-(-6+3i)-(8+2i)=0
We add all the numbers together, and all the variables
(5i+2)-(3i-6)-(2i+8)=0
We get rid of parentheses
5i-3i-2i+2+6-8=0
We add all the numbers together, and all the variables
=0
i=0/1
i=0
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