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(2+5i)/(6-3i)=0
Domain of the equation: (6-3i)!=0We add all the numbers together, and all the variables
We move all terms containing i to the left, all other terms to the right
-3i!=-6
i!=-6/-3
i!=+2
i∈R
(5i+2)/(-3i+6)=0
We multiply all the terms by the denominator
(5i+2)=0
We get rid of parentheses
5i+2=0
We move all terms containing i to the left, all other terms to the right
5i=-2
i=-2/5
i=-2/5
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