(2+I)(2+I)=

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Solution for (2+I)(2+I)= equation:


Simplifying
(2 + I)(2 + I) = 0

Multiply (2 + I) * (2 + I)
(2(2 + I) + I(2 + I)) = 0
((2 * 2 + I * 2) + I(2 + I)) = 0
((4 + 2I) + I(2 + I)) = 0
(4 + 2I + (2 * I + I * I)) = 0
(4 + 2I + (2I + I2)) = 0

Combine like terms: 2I + 2I = 4I
(4 + 4I + I2) = 0

Solving
4 + 4I + I2 = 0

Solving for variable 'I'.

Factor a trinomial.
(2 + I)(2 + I) = 0

Subproblem 1

Set the factor '(2 + I)' equal to zero and attempt to solve: Simplifying 2 + I = 0 Solving 2 + I = 0 Move all terms containing I to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + I = 0 + -2 Combine like terms: 2 + -2 = 0 0 + I = 0 + -2 I = 0 + -2 Combine like terms: 0 + -2 = -2 I = -2 Simplifying I = -2

Subproblem 2

Set the factor '(2 + I)' equal to zero and attempt to solve: Simplifying 2 + I = 0 Solving 2 + I = 0 Move all terms containing I to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + I = 0 + -2 Combine like terms: 2 + -2 = 0 0 + I = 0 + -2 I = 0 + -2 Combine like terms: 0 + -2 = -2 I = -2 Simplifying I = -2

Solution

I = {-2, -2}

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