(2+i)(-7+5i)=

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Solution for (2+i)(-7+5i)= equation: 


Simplifying
(2 + i)(-7 + 5i) = 0

Multiply (2 + i) * (-7 + 5i)
(2(-7 + 5i) + i(-7 + 5i)) = 0
((-7 * 2 + 5i * 2) + i(-7 + 5i)) = 0
((-14 + 10i) + i(-7 + 5i)) = 0
(-14 + 10i + (-7 * i + 5i * i)) = 0
(-14 + 10i + (-7i + 5i2)) = 0

Combine like terms: 10i + -7i = 3i
(-14 + 3i + 5i2) = 0

Solving
-14 + 3i + 5i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(-2 + -1i)(7 + -5i) = 0


Subproblem 1
Set the factor '(-2 + -1i)' equal to zero and attempt to solve:

Simplifying
-2 + -1i = 0

Solving
-2 + -1i = 0

Move all terms containing i to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1i = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1i = 0 + 2
-1i = 0 + 2

Combine like terms: 0 + 2 = 2
-1i = 2

Divide each side by '-1'.
i = -2

Simplifying
i = -2

Subproblem 2
Set the factor '(7 + -5i)' equal to zero and attempt to solve:

Simplifying
7 + -5i = 0

Solving
7 + -5i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -5i = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -5i = 0 + -7
-5i = 0 + -7

Combine like terms: 0 + -7 = -7
-5i = -7

Divide each side by '-5'.
i = 1.4

Simplifying
i = 1.4
Solution
i = {-2, 1.4}

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