(2+i)(3+i)=a+bi

Solution for (2+i)(3+i)=a+bi equation:

Simplifying
(2 + i)(3 + i) = a + bi

Multiply (2 + i) * (3 + i)
(2(3 + i) + i(3 + i)) = a + bi
((3 * 2 + i * 2) + i(3 + i)) = a + bi
((6 + 2i) + i(3 + i)) = a + bi
(6 + 2i + (3 * i + i * i)) = a + bi
(6 + 2i + (3i + i2)) = a + bi

Combine like terms: 2i + 3i = 5i
(6 + 5i + i2) = a + bi

Solving
6 + 5i + i2 = a + bi

Solving for variable 'i'.

Reorder the terms:
6 + -1a + -1bi + 5i + i2 = a + bi + -1a + -1bi

Reorder the terms:
6 + -1a + -1bi + 5i + i2 = a + -1a + bi + -1bi

Combine like terms: a + -1a = 0
6 + -1a + -1bi + 5i + i2 = 0 + bi + -1bi
6 + -1a + -1bi + 5i + i2 = bi + -1bi

Combine like terms: bi + -1bi = 0
6 + -1a + -1bi + 5i + i2 = 0

The solution to this equation could not be determined.