(2+i)-(4-3i)=(-2-4i)

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Solution for (2+i)-(4-3i)=(-2-4i) equation: 



(2+i)-(4-3i)=(-2-4i)

We move all terms to the left:

(2+i)-(4-3i)-((-2-4i))=0

We add all the numbers together, and all the variables

(i+2)-(-3i+4)-((-4i-2))=0

We get rid of parentheses

i+3i-((-4i-2))+2-4=0



We calculate terms in parentheses: -((-4i-2)), so:

(-4i-2)

We get rid of parentheses

-4i-2

Back to the equation:

-(-4i-2)



We add all the numbers together, and all the variables

4i-(-4i-2)-2=0

We get rid of parentheses

4i+4i+2-2=0

We add all the numbers together, and all the variables

8i=0

i=0/8

i=0

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