(2+i)z+i=4i

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Solution for (2+i)z+i=4i equation:


Simplifying
(2 + i) * z + i = 4i

Reorder the terms for easier multiplication:
z(2 + i) + i = 4i
(2 * z + i * z) + i = 4i

Reorder the terms:
(iz + 2z) + i = 4i
(iz + 2z) + i = 4i

Reorder the terms:
i + iz + 2z = 4i

Solving
i + iz + 2z = 4i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4i' to each side of the equation.
i + iz + -4i + 2z = 4i + -4i

Reorder the terms:
i + -4i + iz + 2z = 4i + -4i

Combine like terms: i + -4i = -3i
-3i + iz + 2z = 4i + -4i

Combine like terms: 4i + -4i = 0
-3i + iz + 2z = 0

Add '-2z' to each side of the equation.
-3i + iz + 2z + -2z = 0 + -2z

Combine like terms: 2z + -2z = 0
-3i + iz + 0 = 0 + -2z
-3i + iz = 0 + -2z
Remove the zero:
-3i + iz = -2z

Combine like terms: -2z + 2z = 0
-3i + iz + 2z = 0

The solution to this equation could not be determined.

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