(2+i)z=3z+i

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Solution for (2+i)z=3z+i equation:


Simplifying
(2 + i) * z = 3z + i

Reorder the terms for easier multiplication:
z(2 + i) = 3z + i
(2 * z + i * z) = 3z + i

Reorder the terms:
(iz + 2z) = 3z + i
(iz + 2z) = 3z + i

Reorder the terms:
iz + 2z = i + 3z

Solving
iz + 2z = i + 3z

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
iz + -1i + 2z = i + -1i + 3z

Reorder the terms:
-1i + iz + 2z = i + -1i + 3z

Combine like terms: i + -1i = 0
-1i + iz + 2z = 0 + 3z
-1i + iz + 2z = 3z

Add '-2z' to each side of the equation.
-1i + iz + 2z + -2z = 3z + -2z

Combine like terms: 2z + -2z = 0
-1i + iz + 0 = 3z + -2z
-1i + iz = 3z + -2z

Combine like terms: 3z + -2z = 1z
-1i + iz = 1z

Combine like terms: 1z + -1z = 0
-1i + iz + -1z = 0

The solution to this equation could not be determined.

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