(2+j)(3+j)=

Solution for (2+j)(3+j)= equation:

Simplifying
(2 + j)(3 + j) = 0

Multiply (2 + j) * (3 + j)
(2(3 + j) + j(3 + j)) = 0
((3 * 2 + j * 2) + j(3 + j)) = 0
((6 + 2j) + j(3 + j)) = 0
(6 + 2j + (3 * j + j * j)) = 0
(6 + 2j + (3j + j2)) = 0

Combine like terms: 2j + 3j = 5j
(6 + 5j + j2) = 0

Solving
6 + 5j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(3 + j)(2 + j) = 0

Subproblem 1
Set the factor '(3 + j)' equal to zero and attempt to solve:

Simplifying
3 + j = 0

Solving
3 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + j = 0 + -3
j = 0 + -3

Combine like terms: 0 + -3 = -3
j = -3

Simplifying
j = -3
Subproblem 2
Set the factor '(2 + j)' equal to zero and attempt to solve:

Simplifying
2 + j = 0

Solving
2 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + j = 0 + -2
j = 0 + -2

Combine like terms: 0 + -2 = -2
j = -2

Simplifying
j = -2
Solution
j = {-3, -2}