(2+r)+(4+r)+r=150

Solution for (2+r)+(4+r)+r=150 equation:

Simplifying
(2 + r) + (4 + r) + r = 150

Remove parenthesis around (2 + r)
2 + r + (4 + r) + r = 150

Remove parenthesis around (4 + r)
2 + r + 4 + r + r = 150

Reorder the terms:
2 + 4 + r + r + r = 150

Combine like terms: 2 + 4 = 6
6 + r + r + r = 150

Combine like terms: r + r = 2r
6 + 2r + r = 150

Combine like terms: 2r + r = 3r
6 + 3r = 150

Solving
6 + 3r = 150

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3r = 150 + -6

Combine like terms: 6 + -6 = 0
0 + 3r = 150 + -6
3r = 150 + -6

Combine like terms: 150 + -6 = 144
3r = 144

Divide each side by '3'.
r = 48

Simplifying
r = 48