(2+u)(2+u)=

Solution for (2+u)(2+u)= equation:

Simplifying
(2 + u)(2 + u) = 0

Multiply (2 + u) * (2 + u)
(2(2 + u) + u(2 + u)) = 0
((2 * 2 + u * 2) + u(2 + u)) = 0
((4 + 2u) + u(2 + u)) = 0
(4 + 2u + (2 * u + u * u)) = 0
(4 + 2u + (2u + u2)) = 0

Combine like terms: 2u + 2u = 4u
(4 + 4u + u2) = 0

Solving
4 + 4u + u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(2 + u)(2 + u) = 0

Subproblem 1
Set the factor '(2 + u)' equal to zero and attempt to solve:

Simplifying
2 + u = 0

Solving
2 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + u = 0 + -2
u = 0 + -2

Combine like terms: 0 + -2 = -2
u = -2

Simplifying
u = -2
Subproblem 2
Set the factor '(2 + u)' equal to zero and attempt to solve:

Simplifying
2 + u = 0

Solving
2 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + u = 0 + -2
u = 0 + -2

Combine like terms: 0 + -2 = -2
u = -2

Simplifying
u = -2
Solution
u = {-2, -2}