(2+w)(3w-1)=0

Solution for (2+w)(3w-1)=0 equation:

(2+w)(3w-1)=0

We add all the numbers together, and all the variables

(w+2)(3w-1)=0

We multiply parentheses ..

(+3w^2-1w+6w-2)=0

We get rid of parentheses

3w^2-1w+6w-2=0

We add all the numbers together, and all the variables

3w^2+5w-2=0

a = 3; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·3·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*3}=\frac{-12}{6}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*3}=\frac{2}{6}
=1/3
$