(2+x)(7-x)/(5-x)(4+x)=1

Solution for (2+x)(7-x)/(5-x)(4+x)=1 equation:

(2+x)(7-x)/(5-x)(4+x)=1

We move all terms to the left:

(2+x)(7-x)/(5-x)(4+x)-(1)=0


Domain of the equation: (5-x)(4+x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(4+x!=-5

x∈R


We add all the numbers together, and all the variables

(x+2)(-1x+7)/(-1x+5)(x+4)-1=0

We multiply parentheses ..

(-1x^2+7x-2x+14)/(-1x+5)(x+4)-1=0

We multiply all the terms by the denominator


(-1x^2+7x-2x+14)-1*(-1x+5)(x+4)=0

We get rid of parentheses

-1x^2+7x-2x-1*(-1x+5)(x+4)+14=0

We multiply parentheses ..

-1x^2-1*(-1x^2-4x+5x+20)+7x-2x+14=0

We add all the numbers together, and all the variables

-1x^2-1*(-1x^2-4x+5x+20)+5x+14=0

We move all terms containing x to the left, all other terms to the right

-1x^2-1*(-1x^2-4x+5x+20)+5x=-14