(2+x)+3=2+(x+3)

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Solution for (2+x)+3=2+(x+3) equation: 



(2+x)+3=2+(x+3)

We move all terms to the left:

(2+x)+3-(2+(x+3))=0

We add all the numbers together, and all the variables

(x+2)-(2+(x+3))+3=0

We get rid of parentheses

x-(2+(x+3))+2+3=0



We calculate terms in parentheses: -(2+(x+3)), so:

2+(x+3)

determiningTheFunctionDomain
(x+3)+2

We get rid of parentheses

x+3+2

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

x-(x+5)+5=0

We get rid of parentheses

x-x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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