(2+x)/(2-x)+(2-x)/(2+x)=17/4

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Solution for (2+x)/(2-x)+(2-x)/(2+x)=17/4 equation: 



(2+x)/(2-x)+(2-x)/(2+x)=17/4

We move all terms to the left:

(2+x)/(2-x)+(2-x)/(2+x)-(17/4)=0



Domain of the equation: (2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-2

x!=-2/-1

x!=+2

x∈R





Domain of the equation: (2+x)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We add all the numbers together, and all the variables

(x+2)/(-1x+2)+(-1x+2)/(x+2)-(+17/4)=0

We get rid of parentheses

(x+2)/(-1x+2)+(-1x+2)/(x+2)-17/4=0

We calculate fractions


((x+2)*(x+2)*4)/((-1x+2)*(x+2)*4)+((-1x+2)*(-1x+2)*4)/((-1x+2)*(x+2)*4)+(-17*(-1x+2)*(x+2))/((-1x+2)*(x+2)*4)=0



We calculate terms in parentheses: +((x+2)*(x+2)*4)/((-1x+2)*(x+2)*4), so:

(x+2)*(x+2)*4)/((-1x+2)*(x+2)*4

We multiply all the terms by the denominator


(x+2)*(x+2)*4)

Back to the equation:

+((x+2)*(x+2)*4))





We calculate terms in parentheses: +((-1x+2)*(-1x+2)*4)/((-1x+2)*(x+2)*4), so:

(-1x+2)*(-1x+2)*4)/((-1x+2)*(x+2)*4

We multiply all the terms by the denominator


(-1x+2)*(-1x+2)*4)

Back to the equation:

+((-1x+2)*(-1x+2)*4))





We calculate terms in parentheses: +(-17*(-1x+2)*(x+2))/((-1x+2)*(x+2)*4), so:

-17*(-1x+2)*(x+2))/((-1x+2)*(x+2)*4

We multiply all the terms by the denominator


-17*(-1x+2)*(x+2))

Back to the equation:

+(-17*(-1x+2)*(x+2)))



We add all the numbers together, and all the variables

-1x+((x+2)*(x+2)*4))+((-1x+2)*(-1x+2)*4))+(-17*(+2)*(x=0

We add all the numbers together, and all the variables

-1x+((x+2)*(x+2)*4))+((-1x+2)*(-1x+2)*4))+(-17*2*(x=0

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