(2+x)/33=(3-x)/2

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Solution for (2+x)/33=(3-x)/2 equation: 



(2+x)/33=(3-x)/2

We move all terms to the left:

(2+x)/33-((3-x)/2)=0

We add all the numbers together, and all the variables

(x+2)/33-((-1x+3)/2)=0

We calculate fractions


x/()+(-((-1x+3)*33)/()=0



We calculate terms in parentheses: +(-((-1x+3)*33)/(), so:

-((-1x+3)*33)/(

We multiply all the terms by the denominator


-((-1x+3)*33)



We calculate terms in parentheses: -((-1x+3)*33), so:

(-1x+3)*33

We multiply parentheses

-33x+99

Back to the equation:

-(-33x+99)



We get rid of parentheses

33x-99

Back to the equation:

+(33x-99)



We get rid of parentheses

x/()+33x-99=0

We multiply all the terms by the denominator


x+33x*()-99*()=0

We add all the numbers together, and all the variables

x+33x*()=0

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