(2+x)/3=(9+x)/5

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Solution for (2+x)/3=(9+x)/5 equation: 



(2+x)/3=(9+x)/5

We move all terms to the left:

(2+x)/3-((9+x)/5)=0

We add all the numbers together, and all the variables

(x+2)/3-((x+9)/5)=0

We calculate fractions


x/()+(-((x+9)*3)/()=0



We calculate terms in parentheses: +(-((x+9)*3)/(), so:

-((x+9)*3)/(

We multiply all the terms by the denominator


-((x+9)*3)



We calculate terms in parentheses: -((x+9)*3), so:

(x+9)*3

We multiply parentheses

3x+27

Back to the equation:

-(3x+27)



We get rid of parentheses

-3x-27

Back to the equation:

+(-3x-27)



We get rid of parentheses

x/()-3x-27=0

We multiply all the terms by the denominator


x-3x*()-27*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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