(2+xi)(3-2i)=(12+5i)

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Solution for (2+xi)(3-2i)=(12+5i) equation:


Simplifying
(2 + xi)(3 + -2i) = (12 + 5i)

Multiply (2 + ix) * (3 + -2i)
(2(3 + -2i) + ix(3 + -2i)) = (12 + 5i)
((3 * 2 + -2i * 2) + ix(3 + -2i)) = (12 + 5i)
((6 + -4i) + ix(3 + -2i)) = (12 + 5i)
(6 + -4i + (3 * ix + -2i * ix)) = (12 + 5i)
(6 + -4i + (3ix + -2i2x)) = (12 + 5i)
(6 + -4i + 3ix + -2i2x) = (12 + 5i)

Remove parenthesis around (12 + 5i)
6 + -4i + 3ix + -2i2x = 12 + 5i

Solving
6 + -4i + 3ix + -2i2x = 12 + 5i

Solving for variable 'i'.

Reorder the terms:
6 + -12 + -4i + -5i + 3ix + -2i2x = 12 + 5i + -12 + -5i

Combine like terms: 6 + -12 = -6
-6 + -4i + -5i + 3ix + -2i2x = 12 + 5i + -12 + -5i

Combine like terms: -4i + -5i = -9i
-6 + -9i + 3ix + -2i2x = 12 + 5i + -12 + -5i

Reorder the terms:
-6 + -9i + 3ix + -2i2x = 12 + -12 + 5i + -5i

Combine like terms: 12 + -12 = 0
-6 + -9i + 3ix + -2i2x = 0 + 5i + -5i
-6 + -9i + 3ix + -2i2x = 5i + -5i

Combine like terms: 5i + -5i = 0
-6 + -9i + 3ix + -2i2x = 0

The solution to this equation could not be determined.

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