(2+y)(2y-3)=0

Solution for (2+y)(2y-3)=0 equation:

Simplifying
(2 + y)(2y + -3) = 0

Reorder the terms:
(2 + y)(-3 + 2y) = 0

Multiply (2 + y) * (-3 + 2y)
(2(-3 + 2y) + y(-3 + 2y)) = 0
((-3 * 2 + 2y * 2) + y(-3 + 2y)) = 0
((-6 + 4y) + y(-3 + 2y)) = 0
(-6 + 4y + (-3 * y + 2y * y)) = 0
(-6 + 4y + (-3y + 2y2)) = 0

Combine like terms: 4y + -3y = 1y
(-6 + 1y + 2y2) = 0

Solving
-6 + 1y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-2 + -1y)(3 + -2y) = 0

Subproblem 1
Set the factor '(-2 + -1y)' equal to zero and attempt to solve:

Simplifying
-2 + -1y = 0

Solving
-2 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1y = 0 + 2
-1y = 0 + 2

Combine like terms: 0 + 2 = 2
-1y = 2

Divide each side by '-1'.
y = -2

Simplifying
y = -2
Subproblem 2
Set the factor '(3 + -2y)' equal to zero and attempt to solve:

Simplifying
3 + -2y = 0

Solving
3 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2y = 0 + -3
-2y = 0 + -3

Combine like terms: 0 + -3 = -3
-2y = -3

Divide each side by '-2'.
y = 1.5

Simplifying
y = 1.5
Solution
y = {-2, 1.5}