(2,4x-0,72)(1,5x+3,6)=0

Solution for (2,4x-0,72)(1,5x+3,6)=0 equation:

(2.4x-0.72)(1.5x+3.6)=0

We multiply parentheses ..

(+2x^2+7.2x-0.72x-2.592)=0

We get rid of parentheses

2x^2+7.2x-0.72x-2.592=0

We add all the numbers together, and all the variables

2x^2+6.48x-2.592=0

a = 2; b = 6.48; c = -2.592;
Δ = b2-4ac
Δ = 6.482-4·2·(-2.592)
Δ = 62.7264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.48)-\sqrt{62.7264}}{2*2}=\frac{-6.48-\sqrt{62.7264}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.48)+\sqrt{62.7264}}{2*2}=\frac{-6.48+\sqrt{62.7264}}{4}
$