(2-2i)(2+2i)=

Solution for (2-2i)(2+2i)= equation:

Simplifying
(2 + -2i)(2 + 2i) = 0

Multiply (2 + -2i) * (2 + 2i)
(2(2 + 2i) + -2i * (2 + 2i)) = 0
((2 * 2 + 2i * 2) + -2i * (2 + 2i)) = 0
((4 + 4i) + -2i * (2 + 2i)) = 0
(4 + 4i + (2 * -2i + 2i * -2i)) = 0
(4 + 4i + (-4i + -4i2)) = 0

Combine like terms: 4i + -4i = 0
(4 + 0 + -4i2) = 0
(4 + -4i2) = 0

Solving
4 + -4i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -4i2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -4i2 = 0 + -4
-4i2 = 0 + -4

Combine like terms: 0 + -4 = -4
-4i2 = -4

Divide each side by '-4'.
i2 = 1

Simplifying
i2 = 1

Take the square root of each side:
i = {-1, 1}