(2-2x+3x)/6=2

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Solution for (2-2x+3x)/6=2 equation: 



(2-2x+3x)/6=2

We move all terms to the left:

(2-2x+3x)/6-(2)=0

We add all the numbers together, and all the variables

(x+2)/6-2=0

We multiply all the terms by the denominator


(x+2)-2*6=0

We add all the numbers together, and all the variables

(x+2)-12=0

We get rid of parentheses

x+2-12=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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