(2-2y)=5(2y-2)

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Solution for (2-2y)=5(2y-2) equation: 



(2-2y)=5(2y-2)

We move all terms to the left:

(2-2y)-(5(2y-2))=0

We add all the numbers together, and all the variables

(-2y+2)-(5(2y-2))=0

We get rid of parentheses

-2y-(5(2y-2))+2=0



We calculate terms in parentheses: -(5(2y-2)), so:

5(2y-2)

We multiply parentheses

10y-10

Back to the equation:

-(10y-10)



We get rid of parentheses

-2y-10y+10+2=0

We add all the numbers together, and all the variables

-12y+12=0

We move all terms containing y to the left, all other terms to the right

-12y=-12

y=-12/-12

y=1

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