(2-3)/(z+3)

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Solution for (2-3)/(z+3) equation: 


D( z )

z+3 = 0

z+3 = 0

z+3 = 0

z+3 = 0 // - 3

z = -3

z in (-oo:-3) U (-3:+oo)

(2-3)/(z+3) = 0

-1/(z+3) = 0

z belongs to the empty set

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