(2-3i)(4-6i)=0

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Solution for (2-3i)(4-6i)=0 equation: 



(2-3i)(4-6i)=0

We add all the numbers together, and all the variables

(-3i+2)(-6i+4)=0

We multiply parentheses ..

(+18i^2-12i-12i+8)=0

We get rid of parentheses

18i^2-12i-12i+8=0

We add all the numbers together, and all the variables

18i^2-24i+8=0

a = 18; b = -24; c = +8;
Δ = b2-4ac
Δ = -242-4·18·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{24}{36}=2/3$

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