(2-3i)=-(6+5i)

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Solution for (2-3i)=-(6+5i) equation: 



(2-3i)=-(6+5i)

We move all terms to the left:

(2-3i)-(-(6+5i))=0

We add all the numbers together, and all the variables

(-3i+2)-(-(5i+6))=0

We get rid of parentheses

-3i-(-(5i+6))+2=0



We calculate terms in parentheses: -(-(5i+6)), so:

-(5i+6)

We get rid of parentheses

-5i-6

Back to the equation:

-(-5i-6)



We get rid of parentheses

-3i+5i+6+2=0

We add all the numbers together, and all the variables

2i+8=0

We move all terms containing i to the left, all other terms to the right

2i=-8

i=-8/2

i=-4

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